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Silver Isotope With 60 Neutrons

The concerned silver nuclide with 61 neutrons is $\ce{^108_47Ag}$. This nuclide with 47 protons and 61 neutrons lies in the so-called valley of β-stability.

Chart of stable nuclides
Image taken from Choppin, Liljenzin, Rydberg: Radiochemistry and Nuclear Chemical science, tertiary edition (2002), p. 42

Nuclides on right side of the valley (higher neutron numbers) are unstable to decay past β emission. Nuclides on the left side are unstable to β+ decay or electron capture.

Generally, for isobars (i.east. nuclides with a constant mass number $A$), the binding energy $E$ every bit a role of the atomic number $Z$ describes a parabola:

isobar cut across the valley of β-stability
Image taken from Choppin, Liljenzin, Rydberg: Radiochemistry and Nuclear Chemical science, third edition (2002), p. 52

The most stable nuclides lie at the bottom of the valley (but not necessarily exactly at the minimum of the parabola).

This diagram is right for nuclides with odd mass number $A$ (i.due east. with even $Z$ and odd $Northward$, or with odd $Z$ and fifty-fifty $Northward$). For nuclides with fifty-fifty $A$, however, two different parabolas exist, depending on whether the nuclides have even $Z$ and even $N$ or odd $Z$ and odd $N$:

Isobar parabolas
Image adapted from Choppin, Liljenzin, Rydberg: Radiochemistry and Nuclear Chemistry, third edition (2002), p. 52

Nuclides with fifty-fifty $Z$ and even $N$ (ee) are more than stable (i.e. accept a larger nucleon binding energy) than nuclides with odd $Z$ and odd $Due north$ (oo).

The case (IV) with 2 parabolas besides applies to the question. The stable nuclide $\ce{^108_46Pd}$ has 46 protons and 62 neutrons (even-fifty-fifty). The nuclide considered in the question, $\ce{^108_47Ag}$, has 47 protons and 61 neutrons (odd-odd). The next neighbour, $\ce{^108_47Cd}$ has 48 protons and lx neutrons (even-fifty-fifty) and is stable.

Therefore, $\ce{^108_47Ag}$ is unstable to β decay to $\ce{^108_48Cd}$ $(97.65\ \%)$ as well as to β+ decay to $\ce{^108_46Pd}$ $(2.35\ \%)$.

Since $\ce{^108_47Ag}$ is radioactive with a short half-life of about $2.37\ \mathrm{min}$, it doesn't be in nature (except equally an activation product in trace amounts).

Silver Isotope With 60 Neutrons,

Source: https://chemistry.stackexchange.com/questions/59428/cant-silver-have-61-neutrons

Posted by: tuckeramento94.blogspot.com

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